Determination of BOD of water
Aim
To determine the dissolved oxygen concentration and
biological oxygen demand of pond water
Principle
Dissolved oxygen of water is of paramount importance to all living organisms and is considered to be a factor which to a greater extent can reveal the nature of the whole aquatic system at a glance. Dissolved oxygen is used as an indicator of the health of a water body. Higher dissolved oxygen concentrations are correlated with high productivity and little pollution. The presence of DO in water is mainly due to Direct diffusion from air and by Photosynthetic evolution by aquatic autotrophs.
The first one is purely a physical process and depends on
the solubility of oxygen under the influence of temperature, salinity, water
movement, whereas the later is a biological process and depends on the
availability of light and rate of metabolic processes resulting in diurnal
fluctuations.
Two methods are commonly used to determine DO concentration:
The iodometric method which is a titration-based method and The membrane
electrode procedure. In the Iodometric
method, divalent manganese solution is added to water, followed by addition of
strong alkali in a glass-stopper bottle. DO rapidly oxidize an equivalent
amount of the dispersed divalent manganese hydroxide precipitates to hydroxides
of higher valence states. In acidic conditions, in the presence of iodide ions,
the oxidized manganese reverts to the divalent state and iodine equivalent of
the original DO content get liberated. The iodine is then titrated with a
stranded solution of thiosulfate and the titration end point can be detected using
a starch indicator. Winkler Method uses
titration to determine dissolved oxygen in the water sample.
Biochemical oxygen demand (BOD) is the amount of dissolved
oxygen needed or demanded by aerobic organisms to break down organic material
present in a given sample at certain temperature over a specific time
period. It is a good index of organic pollution. If the amount of
organic matter in a sewage is more, then more oxygen will be utilised by
bacteria to degrade it.
BOD is calculated by keeping a sample of water containing a
known amount of dissolved oxygen for five days in dark under aerobic conditions
at 20OC. The oxygen content is measured again and BOD
calculated. Since nitrification consumes oxygen significantly, it will
result in over estimation of BOD and must be checked by adding 1 ml of 0.5%
solution of Allyl thourea. In the water Samples where more than 70% of
initial oxygen is consumed, it is necessary to aerate/oxygenate/dilute the
sample with BOD free water to avoid oxygen stress.
BOD level in mg/litre Quality of water
1 - 2
- Very Good
3 - 5
- Fair
6-9
- Poor
100 or more
- Very Poor
Reagents required
·
Manganese
Sulphate solution - 48 g MnSO4.4H2O or 40 g MnSO4.2H2O or 36,4 g MnSO4.H2O in 100
ml distilled water
·
Alkali
- iodide – azide reagent
o
Solution
A - 500 mg NaOH and 135 g Sosium Iodide in 1 litre distilled water
o
Solution
B - 10 g Sodium Azide in 40 ml distilled water
o
Solution
A and B are mixed to get alkali -iodide - azide solution
·
Concentrated
sulphuric acid
·
0.025
N Sodium Thiosulphate solution
·
Starch
Solution - 2 g soluble starch in 100 ml distilled water.
·
Allyl
Thio Urea Solution (0.05%)
·
Sulphuric
acid (1N) - 2.8 ml of concentrated H2SO4 added to 100 ml distilled water
·
Sodium
hydroxide (1 N) - 4 g of NaOH in 100 ml distilled water
Materials required
Water Sample, Pipette, Titration assembly, BOD bottle, BOD
Incubator, Flasks, etc
Procedure
- pH of water sample was adjusted
to neutral using 1N acid or 1 N alkali Solution.
- The pond water sample was
filled in 2 BOD bottles without any bubble formation.
- 1 ml alkyl thiourea was added
to 1 bottle.
- 2 ml of manganese sulphate was
added slowly to the bottle by inserting pipette below the surface of water
so that no air bubbles are introduced via the pipette.
- 2 ml of alkali - iodide - azide
reagent was added in the same manner. The bottle was stoppered with
care so as not to allow air entry in to the bottle and mixed the sample by
inverting several times. If oxygen is present, a brownish - orange
colour of precipitate or floc will appear.
- The precipitates formed are
dissolved by adding 2 ml of concentrated sulphuric acid by keeping the
pipette very near to sample surface. Again after carefully
stoppering, the bottle was inverted several times to dissolve the
floc.
- 50 ml of the sample from the
bottle was titrated with 0.025 N sodium thiosulphate, till a pale straw
colour is formed.
- 2 ml of starch solution was
added, and a blue colour formed
- Titration is continued until
the sample colour turns clear.
- The burette reading was noted.
·
Calculation of D.O. in mg/Liter = 8 X 100
X N/V X v
§ V
= Volume of sample taken
§ v = Volume of 0.025N Sodium thiosulphate solution used
§ N = Normality of titrant = 0.025
§ 8
is constant (1ml of 0.025N Sodium thiosulphate solution is equivalent to
0.2mg oxygen).
- The concentration of dissolved
oxygen in the sample is equivalnet to the volume of 0.025 N sodium
thiosulphate used. Each ml of 0.025 N sodium thiosulphate
added is equal to 1 mg/L Dissolved oxygen. This is recorded as Dissolved
Oxygen (D1).
- The other 2 bottles are kept in
BOD incubator at 20OC and after 5 days, the dissolved oxygen
was determined by the above method and the value was recorded as Dissolved
Oxygen (D2).
- The BOD of water in mg/Liter was calculated as BOD = D1-D2
- D1 is the initial dissolved
oxygen concentration of the sample before 5 days incubation and D2 is the
concentration after 5 days of incubation.
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